invert_tree

Invert a binary tree.

     4
   /   \
  2     7
 / \   / \
1   3 6   9

to

     4
   /   \
  7     2
 / \   / \
9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew),
but you can’t invert a binary tree on a whiteboard so fuck off.

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/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
if(root == NULL)
return NULL;
root->left = invertTree(root->left);
root->right = invertTree(root->right);
TreeNode *tmp = root->left;
root->left = root->right;
root->right = tmp;
return root;
}
};

这到题目不难,主要用了递归的思想,反转二叉树就是每个节点下的左右儿子,我们需要从他的最下面开始反转,这里用递归就很合适。

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